There are only a couple of Lines and Angles questions tested on the SAT Math section. The questions are usually easy and should not pose a challenge to you.

∠2 = ∠4

∠5 = ∠7

∠6 = ∠8

∠1 = ∠5

∠2 = ∠6

∠3 = ∠7

∠4 = ∠8

∠1 = ∠7

∠2 = ∠8

∠4 = ∠6

∠3 = ∠5

So, putting all information together:

∠1, 3, 5 and 7 are congruent;

∠2, 4, 6 and 8 are congruent.

**The opposite of all of this is also true: **if you don't know if two lines are parallel - look at the alternate interior or exterior angles. If they are congruent, the lines are parallel.

Statement A: ∠3 + ∠4 + ∠5 = 131°

Statement B: ∠6 + ∠7 + ∠8 = 131°

Refer to the figure and two statements. Evaluate ∠1 + ∠2. 82°

A.

** Solution:** Let’s consider the first statement by itself. ∠2, ∠3, ∠4, and ∠5 together form a straight angle, so their degree measures a total 180°.

∠2 + ∠3 + ∠4 + ∠5 = 180°

∠2 + 131° = 180°

∠2 = 49°

Without further information, no other angle measures, including that of ∠1, can be found. So, let’s consider the second statement. ∠1, ∠6, ∠7, and ∠8 together form a straight angle, so their degree measures a total 180°.

∠1 + ∠6 + ∠7 + ∠8 = 180°

∠1 + 131° = 180°

∠1 = 49°

We’ve found both ∠1 and ∠2, so all we have to do is add them together to solve the problem:

∠1+ ∠2 = 49° + 49° = 98°

**The correct answer is B.**

Statement A: ∠2 = 89°

Statement B: ∠3 = ∠6

Given the above figure and two statements, which of the following is true?Line m is perpendicular to line t

A.

** Solution:** Statement A alone establishes by definition that line l is not perpendicular to line t, but it does not establish any relationship between line m and line t.

By Statement B alone, we know line l is parallel to line m because alternating interior angles are congruent., line l is parallel to line m. ∠2 and ∠6 are corresponding angles formed by a transversal across parallel lines, so ∠6 = ∠2 = 89°. ∠6 is not a right angle, so line m is not perpendicular to line t and **B is the correct answer.**

Consider the line diagram shown at right. Which of the following pieces of information is enough to prove that AB is parallel to CD?∠1 = ∠3

A.

** Solution:** By learning that ∠4 = 120° and ∠8 = 60°, we have enough information to determine that ∠1 = 60° (because it forms a straight angle with ∠4 ) and that ∠7 = 120° (since it forms a straight angle with ∠8 ). At this point, we can see that the pairs of corresponding angles, angles 1 and 8 and angles 4 and 7, match in value. This means that AB is parallel to CD.

∠ABD = 60°. What is ∠DBE? 30°

A.

** Solution:** The sum of ∠ABD, ∠DBE, and ∠EBC equally 180° because they are all on the straight-line AC.

∠ABD + ∠DBE + ∠EBC = 180°

We know that ∠ABD = 60° and that ∠EBC = 90°, so we can substitute in those values.

60° + ∠DBE + 90° = 180°

∠DBE = 30°****

**The correct answer is A.**

The rotation from the initial side to the terminal side is a measure of an angle. The counterclockwise rotation is considered positive. An angle in the clockwise direction is taken as negative. **CO-TERMINAL** angles are the two angles that have the same terminal side.

**RADIANS** and **DEGREES** are units to measure angles. The conversion between these two units can be done using the following equation.

\(\frac{1}{360} degree=\frac{1}{2\pi}radian\) ** OR **

\(\frac{1}{180} degree=\frac{1}{\pi}radian\)

To convert from degrees to radians and vice versa, we need the following:

Deg. = Rad. x \(\frac{180}{\pi}\)

Rad. = Deg. x \(\frac{\pi}{180}\)

For example, if we need to convert 50 degrees to radians, we need to multiply the degree measure by \(\frac{\pi}{180}\) ,

i.e. 50°= 50 x \(\frac{\pi}{180}rad = \frac{5\pi}{18}rad\)

Similarly, if we need to convert radians into degrees, we need to multiply the radian measure by \(\frac{\pi}{180}\)

Some important conversions are:

- \(30^{\circ}=\frac{\pi}{6}rad.\)
- \(45^{\circ}=\frac{\pi}{4}rad.\)
- \(60^{\circ}=\frac{\pi}{3}rad.\)
- \(90^{\circ}=\frac{\pi}{2}rad.\)
- \(180^{\circ}=\pi rad.\)

Example: In the xy-plane, O is the center of the circle, and the measure of radians. What is the value of a?

By the distance formula, the length of radius OA is \(\sqrt{\sqrt{3^{2}}+1^{2}}=2\)

Thus, SIN (∠AOB) = \(\frac{1}{2}\)

Therefore ∠AOB is 30°, which is equal to \(30\frac{(\pi)}{180}=\frac{\pi}{6}radians\)

Hence, the value of a is 6.